Ryan314 1 Report post · CID: 634063330640 Posted April 7, 2016 Hello all, Been quite a long time since I've posted on here. Hope everyone is doing well! I figured what better place to turn to than the knowledgeable users of testmy.net?! I'm in a networking class and one of our homework problems has me stumped. I understand the general concept of subnetting but I am struggling with this. I get 182.168.0.0 /16 translates to a subnet mask of 255.255.0.0 (/16 in CIDR) I also understand we're subnetting the whole third octet but this part confused me as we shouldn't need the WHOLE third octet subnetted if we've only got 3 networks with 5 hosts per? The problem is below. Any assistance would be greatly appreciated as I have quite a few more similar problems to work through. P.S if this is the wrong section I apologize A router at your main company location is connected to your provider and 3 internal locations. The network address from your provider is 182.168.0.0/16. Each location has a maximum of 5 nodes Assume you are using the entire byte 3 for subnets A. What are the 1st 3 and last 3 possible subnets to the three locations? B. Assume you have decided to use the 1st 3 subnets B1. what are the 1st and last 4 host addresses on each subnet? B2. what is the broadcast address on each subnet? C. What is the new subnet mask? Quote Share this post Link to post Share on other sites
nanobot 125 Report post · CID: 1588699570045 Posted April 7, 2016 So what exactly is the issue? If you're using the entire third byte as your subnet block, your new mask would be 255.255.255.0, or /24. Which means the first subnet is 182.168.0.0/24, then 182.168.1.0/24, 182.168.2.0/24, etc. They're probably asking you to use the entire third block so that it makes an easy beginner question. Otherwise you would be able to get away with a 255.255.255.248 (/29) instead. Which would give you exactly 5 host addresses, 1 gateway address, 1 network address, and 1 broadcast address. The problem with this is that it's not as easy of a beginner question. (Your first subnet is 182.168.0.0 to 182.168.0.7, then 182.168.0.8 to 182.168.0.15, etc.) Thanks, EBrown Quote Share this post Link to post Share on other sites
