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Ryan314

Subnetting assignment

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Hello all, 

Been quite a long time since I've posted on here. Hope everyone is doing well! I figured what better place to turn to than the knowledgeable users of testmy.net?! 

I'm in a networking class and one of our homework problems has me stumped. I understand the general concept of subnetting but I am struggling with this. 

 

I get 182.168.0.0 /16 translates to a subnet mask of 255.255.0.0 (/16 in CIDR) I also understand we're subnetting the whole third octet but this part confused me as  we shouldn't need the WHOLE third octet subnetted if we've only got 3 networks with 5 hosts per?  The problem is below. Any assistance would be greatly appreciated as I have quite a few more similar problems to work through. P.S if this is the wrong section I apologize :) 

 


A router at your main company location is connected to your provider and 3 internal locations. The network address from your provider is 182.168.0.0/16. Each location has a maximum of 5 nodes

Assume you are using the entire byte 3 for subnets

A. What are the 1st 3 and last 3 possible subnets to the three locations?
B. Assume you have decided to use the 1
st 3 subnets
B1. what are the 1
st and last 4 host addresses on each subnet?
B2. what is the broadcast address on each subnet?
C. What is the new subnet mask?

 

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So what exactly is the issue? If you're using the entire third byte as your subnet block, your new mask would be 255.255.255.0, or /24.

 

Which means the first subnet is 182.168.0.0/24, then 182.168.1.0/24, 182.168.2.0/24, etc.

 

They're probably asking you to use the entire third block so that it makes an easy beginner question. Otherwise you would be able to get away with a 255.255.255.248 (/29) instead. Which would give you exactly 5 host addresses, 1 gateway address, 1 network address, and 1 broadcast address. The problem with this is that it's not as easy of a beginner question. (Your first subnet is 182.168.0.0 to 182.168.0.7, then 182.168.0.8 to 182.168.0.15, etc.)

 

Thanks,

EBrown

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