RAINMAKA Posted September 19, 2006 CID Share Posted September 19, 2006 i was hoping that some people out there might be able to help me with a few of my math problems. 1) 2cos(x) = sqrt(2); Solve for x 2) Simplify log27-log8 3) 6e^3x = 3e^5x; Solve for x 4) Find the equation of an exponential function where f(2)=4 and f(5)=108 5) Find the polynomial with x-intercepts of 1 & 4, & y-intercept of -2 Quote Link to comment Share on other sites More sharing options...
tommie gorman Posted September 19, 2006 CID Share Posted September 19, 2006 RAINMAKA having been out of school for a while, it would be helpful if I knew what type of Math it is. Algebra or what? Quote Link to comment Share on other sites More sharing options...
RAINMAKA Posted September 19, 2006 Author CID Share Posted September 19, 2006 calculus Quote Link to comment Share on other sites More sharing options...
water Posted September 19, 2006 CID Share Posted September 19, 2006 I'm on it, I'm assuming you are allowed to use a calculator? Quote Link to comment Share on other sites More sharing options...
tommie gorman Posted September 19, 2006 CID Share Posted September 19, 2006 RAINMAKA is allowed, but your not water. The problems with calculators is, it will never show your problem solving. Quote Link to comment Share on other sites More sharing options...
water Posted September 20, 2006 CID Share Posted September 20, 2006 I'm sorry RAIN, it has been too long since I did calc, I keep coming up with wrong answers.... I'll keep trying but for now it's a no go Quote Link to comment Share on other sites More sharing options...
tommie gorman Posted September 20, 2006 CID Share Posted September 20, 2006 PM swimmer or Van, I bet they could do it! They's the man! Quote Link to comment Share on other sites More sharing options...
karthic Posted September 20, 2006 CID Share Posted September 20, 2006 @ RAINMAKA Here are my answers for some problems you 've posted (if i am allowed) 1) 2cos(x) = sqrt(2); Solve for x ans. 2cos(x)=sqrt(2) =1.414 therefore cos(x)=1.414/2=0.707 x=cos^-1(0.707) =45.00865166 now comes 2) Simplify log27-log8 use calculator dude or longman tables if calcs are not allowed to find the values of both log 27 and log 8 and then find the difference in my calculator there were both log to the base as exponential and to the base 10 i couldn't remember the default log base to be taken coz i am too out of school for a very long time!!!!!!!!!!!!!!!!!!!!!! and 3) 6e^3x = 3e^5x; Solve for x take log on both sides reducing it to 3x log 6 = 5x log 3 now simplify it dude and here too there is that base problem 4) Find the equation of an exponential function where f(2)=4 and f(5)=108 sorry dude i dont know how to do this!!!!!!!!!!!!!!! finally 5) Find the polynomial with x-intercepts of 1 & 4, & y-intercept of -2 i am making out how can anyone make an equation with two x intercepts and one y intercept!!!!!!!!!!!!!! and again sorry!!!!!!!!!!!!!!!! hope you got the answers for atleast some!!!!!!!!!!!!!! q's!!!!!!!!! pls correct me if i 'm wrong Quote Link to comment Share on other sites More sharing options...
sundar Posted September 20, 2006 CID Share Posted September 20, 2006 3) 6e^3x = 3e^5x; Solve for x 6e^3x=3e^5x 2e^3x=e^5x 2=e^5x.e^(-3x) 2=e^2x taking log on both sides ln(2)=2x x=ln(2)/2 x=.34657 Quote Link to comment Share on other sites More sharing options...
tommie gorman Posted September 20, 2006 CID Share Posted September 20, 2006 Man that looks just like algebra, if I had known some of the abbreviations I could have solved some of it. sqrt=square root cos=?? ^=?? I could do most of this in my head. Just not sure what most of it is. Quote Link to comment Share on other sites More sharing options...
Roco Posted September 20, 2006 CID Share Posted September 20, 2006 I live in dread of loosing a finger, Quote Link to comment Share on other sites More sharing options...
tommie gorman Posted September 20, 2006 CID Share Posted September 20, 2006 If all else fails Roco, we just take off our shoes to count to 10 in the south. Quote Link to comment Share on other sites More sharing options...
Roco Posted September 20, 2006 CID Share Posted September 20, 2006 [ If all else fails Roco, we just take off our shoes to count to 10 in the south. LOL I have heard the south can be a bit uncouth , Quote Link to comment Share on other sites More sharing options...
wingzero2309 Posted September 21, 2006 CID Share Posted September 21, 2006 1) 2cos(x) = sqrt(2); Solve for x x=pi/4 cos(pi/4)=sqrt(2)/2 2* (sqrt(2)/2) = sqrt(2) um..yeah thts the only one i remember how to do lol Quote Link to comment Share on other sites More sharing options...
karthic Posted September 21, 2006 CID Share Posted September 21, 2006 @ wing zero superb man its the best way to solve those type of q's Quote Link to comment Share on other sites More sharing options...
RAINMAKA Posted September 21, 2006 Author CID Share Posted September 21, 2006 thanks alot guys, with ur help i have figured them out Quote Link to comment Share on other sites More sharing options...
tommie gorman Posted September 21, 2006 CID Share Posted September 21, 2006 Man, I would have had them done by X-mas for you. I promise. Quote Link to comment Share on other sites More sharing options...
php Posted September 21, 2006 CID Share Posted September 21, 2006 Man that looks just like algebra, if I had known some of the abbreviations I could have solved some of it. sqrt=square root cos=?? ^=?? I could do most of this in my head. Just not sure what most of it is. cos is cosine, ^ is exponential symbol.. Quote Link to comment Share on other sites More sharing options...
basic Posted September 22, 2006 CID Share Posted September 22, 2006 I don't understand Greek Quote Link to comment Share on other sites More sharing options...
tommie gorman Posted September 22, 2006 CID Share Posted September 22, 2006 Guess maybe it has been longer than I thought. But I still beat most calculators for speed. Quote Link to comment Share on other sites More sharing options...
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